Question

（1）?32x?4÷1x?2?x2?4x2+3x?2（2）1?x2x2?x?6? 9?6x+x22x2+6x+4÷x2?4x+35x2+20x+20

（1）?32x?4÷1x?2?x2?4x2+3x?2（2）1?x2x2?x?6? 9?6x+x22x2+6x+4÷x2?4x+35x2+20x+20．

Answer 1

（1）原式=

?3

2(x?2)

×

x?2

1

×

(x+2)(x?2)

x2+3x?2

=-

3x2?12

2x2+6x?4

；

（2）原式=

?(x+1)(x?1)

(x?3)(x+2)

×

(x?3)2

2(x+1)(x+2)

×

5(x+2)2

(x?3)(x?1)

=-

5

2

．