Question

数学函数问题~~~

已知f(x)是定义在R上周期为2的奇函数,当x属于[0,1)时,f(x)=2^x-1,求值f(log(0.5)6)
过程谢谢~~~

Answer 1

好久没做过数学题了，呵呵，我做做看啊

f(x)是奇数 -> f(log(0.5)6) = -f(-log(0.5)6) 应该对哈
-log((0.5)6) -> log2 6 貌似是这样
T = 2 -> f(log2 6) = f(log2 6 - 2) = f(log2 6 - log2 4) = f(log2 3/2)

3/2 < 2 -> 0 < log2 3/2 < 1 }
x∈[0,1)时，f(x) = 2^x - 1 } -> f(log2 3/2) = 2^log2 3/2 - 1 = 1/2

最后结合第一个式子 -> f(log(0.5)6) = -1/2

呵呵，不知对否，你看着办吧，希望能帮上忙。