若3的x次方=4，3的y次方=6求9的2x-y+27的x-y的值
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3^x = 4
x= log4/log3
3^y = 6
y=log6/log3
2x-y+27
= 2(log4/log3) - log6/log3 + 27
= (log16-log6)/log3 + 27
= log(8/3)/log3 + 27
= log8/log3 -1 +27
= 3log2/log3 +26
x= log4/log3
3^y = 6
y=log6/log3
2x-y+27
= 2(log4/log3) - log6/log3 + 27
= (log16-log6)/log3 + 27
= log(8/3)/log3 + 27
= log8/log3 -1 +27
= 3log2/log3 +26
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