分式的计算
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=(x+y)/[x(x-y)] - (x+y)²(x-y)²/x * 1/(x-y)³
=(x+y)/[x(x-y)] - (x+y)²/x²* 1/(x-y)
=(x²+xy)/[x²(x-y)] - (x+y)²/[x²(x-y)]
=(x²+xy-x²-2xy-y²)/[x²(x-y)]
=-(xy+y²)/[x²(x-y)]
=-(xy+y²)/(x³-x²y)]
=(x+y)/[x(x-y)] - (x+y)²/x²* 1/(x-y)
=(x²+xy)/[x²(x-y)] - (x+y)²/[x²(x-y)]
=(x²+xy-x²-2xy-y²)/[x²(x-y)]
=-(xy+y²)/[x²(x-y)]
=-(xy+y²)/(x³-x²y)]
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