λ取何值时,方程组2x1+λx2?x3=1λx1?x2+x3=24x1+5x2?5x3=?1无解,有唯一解或有无穷多解?并在有无穷
λ取何值时,方程组2x1+λx2?x3=1λx1?x2+x3=24x1+5x2?5x3=?1无解,有唯一解或有无穷多解?并在有无穷多解时写出方程组的通解....
λ取何值时,方程组2x1+λx2?x3=1λx1?x2+x3=24x1+5x2?5x3=?1无解,有唯一解或有无穷多解?并在有无穷多解时写出方程组的通解.
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∵方程组系数矩阵的行列式:
|A|=
|
∴
①当λ≠1且λ≠?
4 |
5 |
②当λ=?
4 |
5 |
. |
A |
|
5r1,?5r2 |
|
r3?r2 |
|
从而:r(A)=2<3=r(
. |
A |
∴方程组无解,
③当λ=1时,
. |
A |
|
r1r2 |
|
r2?2r1,r3?4r1 |
|
r3?3r1, |