5、6、7、8题求大神帮忙解答 最好有详细解题化简过程,微积分还是学不会啊
1个回答
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u=(x+y)/(1-xy)
z'x=u'x/(1+u²)
=(1-xy-(x+y)(-y))/(1-xy)²(1+u²)
=(1+y²)/((1-xy)²+(x+y)²)
z'y=u'y/(1+u²)
=(1-xy-(x+y)(-x))/(1-xy)²(1+u²)
=(1+x²)/((1-xy)²+(x+y)²)
z'x=u'x/(1+u²)
=(1-xy-(x+y)(-y))/(1-xy)²(1+u²)
=(1+y²)/((1-xy)²+(x+y)²)
z'y=u'y/(1+u²)
=(1-xy-(x+y)(-x))/(1-xy)²(1+u²)
=(1+x²)/((1-xy)²+(x+y)²)
追答
(6)同理,复合函数求导法则,
u=x+√(x²+y²),z=lnu
z'x=u'x/u,z'y=u'y/u
(8)同理,先看书,把相关知识理解透了自然就会了。
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