求这个定积分
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let
f(x) = (x^5+2x^3+3x) (cosx)^2
f(-x) = -f(x)
∫(-π/2->π/2) (x^5+2x^3+3x+1) (cosx)^2 dx
=∫(-π/2->π/2) (x^5+2x^3+3x) (cosx)^2 dx +∫(-π/2->π/2) (cosx)^2 dx
=0+∫(-π/2->π/运姿雀2) (cosx)^2 dx
=2∫(0->π/2) (cosx)^2 dx
=∫(0->π/2) (1+cos2x) dx
=[x +(1/2)sin2x]|(0->π/册帆2)
=π/旁早2
f(x) = (x^5+2x^3+3x) (cosx)^2
f(-x) = -f(x)
∫(-π/2->π/2) (x^5+2x^3+3x+1) (cosx)^2 dx
=∫(-π/2->π/2) (x^5+2x^3+3x) (cosx)^2 dx +∫(-π/2->π/2) (cosx)^2 dx
=0+∫(-π/2->π/运姿雀2) (cosx)^2 dx
=2∫(0->π/2) (cosx)^2 dx
=∫(0->π/2) (1+cos2x) dx
=[x +(1/2)sin2x]|(0->π/册帆2)
=π/旁早2
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