有五张卡片分别写有数字33417请问可以组成多少个不同的五位数?
1个回答
2022-07-23
展开全部
33417,这五个数字中有两个3
因此,排列方案中需要减除两个3互换的重复方案
一共可以组成 5!/2! = 60个不同的五位数
~~~
~~~
60个五位数如下:
13347,13374,13437,13473,13734,13743,14337,14373,14733,17334,17343,17433,31347,31374,31437,31473,31734,31743,33147,33174,33417,33471,33714,33741,34137,34173,34317,34371,34713,34731,37134,37143,37314,37341,37413,37431,41337,41373,41733,43137,43173,43317,43371,43713,43731,47133,47313,47331,71334,71343,71433,73134,73143,73314,73341,73413,73431,74133,74313,74331。
因此,排列方案中需要减除两个3互换的重复方案
一共可以组成 5!/2! = 60个不同的五位数
~~~
~~~
60个五位数如下:
13347,13374,13437,13473,13734,13743,14337,14373,14733,17334,17343,17433,31347,31374,31437,31473,31734,31743,33147,33174,33417,33471,33714,33741,34137,34173,34317,34371,34713,34731,37134,37143,37314,37341,37413,37431,41337,41373,41733,43137,43173,43317,43371,43713,43731,47133,47313,47331,71334,71343,71433,73134,73143,73314,73341,73413,73431,74133,74313,74331。
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