1个回答
2010-12-10
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F(x)=g(x)f(x)
F'(x)=g'(x)f(x) + g(x)f(x)'
f(x) = (x^3 +1)(3x^3 -4x +2)
f'(x) = 3x^2(3x^3 -4x +2) + (x^3 +1)(9x^2 -4)
= 9x^5 -12x^3 +6x^2 + 9x^5 -4x^3 +9x^2 -4
= 18x^5 -16x^3 +15x^2 -4
F'(x)=g'(x)f(x) + g(x)f(x)'
f(x) = (x^3 +1)(3x^3 -4x +2)
f'(x) = 3x^2(3x^3 -4x +2) + (x^3 +1)(9x^2 -4)
= 9x^5 -12x^3 +6x^2 + 9x^5 -4x^3 +9x^2 -4
= 18x^5 -16x^3 +15x^2 -4
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