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(1+i))^2=2i
(1+i))^2005=(2i)^1002 × (1+i)=-2^1002 (1+i)
(根号2/(1+i))^2005=- (1-i)/[2^1002.5]
希望以上答案能对你有帮助哦^_^
(1+i))^2005=(2i)^1002 × (1+i)=-2^1002 (1+i)
(根号2/(1+i))^2005=- (1-i)/[2^1002.5]
希望以上答案能对你有帮助哦^_^
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(根号2/(1+i))^2005
=(√2/2-√2i/2)^2005
=(cosπ/4-isinπ/4)^2005
=cos2005π/4-isin2005π/4
=cos(504π+π/4)-isin(504π+π/4)
=cosπ/4-isinπ/4
=√2/2-√2i/2
=(√2/2-√2i/2)^2005
=(cosπ/4-isinπ/4)^2005
=cos2005π/4-isin2005π/4
=cos(504π+π/4)-isin(504π+π/4)
=cosπ/4-isinπ/4
=√2/2-√2i/2
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