1个回答
展开全部
10a(x-y)²-5b(y-x)
=10a(x-y)²-[-5b(x-y)] [变号，找出公因式(x-y)]
=10a(x-y)²+5b(x-y) [去括号，变号]
=(x-y)[10a(x-y)+5b] [提取公因式(x-y)]
=(x-y)(10ax-10ay+5b)
=10a(x-y)²-[-5b(x-y)] [变号，找出公因式(x-y)]
=10a(x-y)²+5b(x-y) [去括号，变号]
=(x-y)[10a(x-y)+5b] [提取公因式(x-y)]
=(x-y)(10ax-10ay+5b)
已赞过
已踩过<
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
|
广告 您可能关注的内容 |
