2个回答
展开全部
sin(A+B)=sinA.cosB+cosA.sinB (1)
sin(A-B)=sinA.cosB-cosA.sinB (2)
(1)+(2)
sin(A+B)+sin(A-B)= 2sinA.cosB
x+2y = A (3)
x-2y =B (4)
(3)+(4)
A+B= 2x
(3)-(4)
A-B = 4y
ie
sin(A+B)+sin(A-B)= 2sinA.cosB
sin(2x)+sin(4y)= 2sin(x+2y).cos(x-2y)
sin(A-B)=sinA.cosB-cosA.sinB (2)
(1)+(2)
sin(A+B)+sin(A-B)= 2sinA.cosB
x+2y = A (3)
x-2y =B (4)
(3)+(4)
A+B= 2x
(3)-(4)
A-B = 4y
ie
sin(A+B)+sin(A-B)= 2sinA.cosB
sin(2x)+sin(4y)= 2sin(x+2y).cos(x-2y)
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询