Question

(x+2y+z)(x-2y-z)结果。过程。速度答！。给分

Answer 1

原式=[x+(2y+zx)][x-(2y+zx)]
=x²-(2y+z)²
=x²-4y²-4yz-z²

Answer 2

(x+2y+z)(x-2y-z)
=[x+(2y+z)]*[x-(2y+z)]
=x^2-(2y+z)^2
=x^2-(4y^2+4yz+z^2)
=x^2-4y^2-4yz-z^2