Question

求解初二下数学题！！！

x 减 x分之（x二次方减y二次方）再加上y分之（x二次方加y二次方）减y
a+2-（2-a分之4）

帮帮忙

Answer 1

x-(x2-y2)/x+(x2+y2)/y-y
= (x-y)+(x三次方-y方x+x方y+y三次方)/xy
=(x-y)+(x-y)三次方/xy
=(x-y)[1+(x-y)平方/xy]

a+2-(2-4/a)
=a+2-2+4/a
=a+4/a
第二题.什么意思?

Answer 2

x-(x^2-y^2)/x+(x^2+y^2)/y-y
= (x-y)+(x^3-y^2*x+x^2*y+y^3)/xy
=(x-y)+(x-y)^3/xy
=(x-y)[1+(x-y)^2/xy]

a+2-(2-4/a)
=a+2-2+4/a
=a+4/a