Question

急！！两道初二因式分解~

1、（x²-1）²+6（1-x²）+9
2、a³+6a²+11a+6
请大家尽快看看，写出详细过程，谢谢！

Answer 1

1, （x²-1）²+6（1-x²）+9
=（x²-1）²-6(x²-1)+9
=(x²-1-3)²
=(x+2)^2(x-2)^2

2, a³+6a²+11a+6
=a^3+6a^2+9a+2a+6
=a(a^2+6a+9)+2(a+3)
=a(a+3)^2+2(a+3)
=(a+3)[a(a+3)+2]
=(a+3)(a^2+3a+2)
=(a+3)(a+1)(a+2)

Answer 2

（x²-1）²+6（1-x²）+9=（x²-1）²-6(x²-1)+9
=(x²-1-3)²
a³+6a²+11a+6
=

Answer 3

1、（x²-1）²+6（1-x²）+9
=(x²-1）²-6（x²-1）+9
=[(x²-1）-3]²
=(x²-4）²

Answer 4

1、（x²-1）²+6（1-x²）+9
=(x²-1）²-6（x²-1）+9
=[(x²-1）-3]²
=(x²-4）²
=(x+2)²(x-2)²
2、a³+6a²+11a+6
=（a+3）(a²+3a+2)
=(a+3)(a+2)(a+1)

Answer 5

1、=（x²-1）²-6(x²-1）+9=（x²-1-3）²=（x²-4）²
2、a³+6a²+11a+6=a³+a²+5a²+5a+6a+6=a²(a+1)+5a(a+1)+6(a+1)=(a+1)(a²+5a+6)=(a+1)(a+2)(a+3)

Answer 6

1原式=(1-x2)2+6(1-x2)+3乘3
=(1-X2+3)的平方