Question

用C语言采用递归方法求sum=1+ 1/(1*2) + 1/(2*3) + 1/(3*4) +…… + 1/(n*(n+1))的值

#include <stdio.h>
float sum(int n)
{
float s;
s=sum(n);
if (n=1)
s=3/2;
else s=sum(n-1)+(1/n*(n+1));
return(s);
}
void main()
{
int n;
float s;
s=sum(n);
scanf("%d\n",n);
printf("%f,\n",s);
}
这个有什么错误的地方？

Answer 1

#include <stdio.h>
float sum(int n)
{
float s;
//s=sum(n);
if (n==0)
{
s=1;
}
else
{
s=1.0/(n*(n+1))+sum(n-1);
}
return s;
}

void main()
{
int n;
float s;
scanf("%d",&n);
s=sum(n);
printf("%f,\n",s);
}
这样改