求定积分∫1 →1/√2 √1-x^2/x^2dx！！！
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I = ∫<1 →1/√2> [√(1-x^2)/x^2]dx (x = sinu, dx = cosudu)
= ∫<π/2 →π/4> [(cosu)^2/(sinu)^2]du
= ∫<π/2 →π/4> (cotu)^2du = ∫<π/2 →π/4> [(cscu)^2-1]du
= -[cotu + u]<π/2 →π/4> = -(1+π/4) + (0+π/2) = π/4 - 1
= ∫<π/2 →π/4> [(cosu)^2/(sinu)^2]du
= ∫<π/2 →π/4> (cotu)^2du = ∫<π/2 →π/4> [(cscu)^2-1]du
= -[cotu + u]<π/2 →π/4> = -(1+π/4) + (0+π/2) = π/4 - 1
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