Question

已知函数f(x)=sin(x+派/6)+2sin平方x/2.求函数f(x)的单调递增区间?

Answer 1

函数f(x)=sin(x+派/6)+2sin^2(x/2)
= sin(x+派/6)+1-cosx
=sinxcos派/6+cosxsin派/6+1-cosx
= sinxcos派/6-cosxsin派/6+1
= sin(x-派/6)+1,
2k派-派/2