已知x^2-5x+1=0,求值x^2+1/x^2
2个回答
展开全部
解:
因为x^2-5x+1=0
则x^2=5x-1
进而
x^2+1/x^2
=(5x-1)+[1/(5x-1)]
=[(5x-1)^2+1]/(5x-1)
=[(25x^2)-2(5x-1)]/(5x-1)
=[(25x^2)/(5x-1)]-2
=25-2
=23
因为x^2-5x+1=0
则x^2=5x-1
进而
x^2+1/x^2
=(5x-1)+[1/(5x-1)]
=[(5x-1)^2+1]/(5x-1)
=[(25x^2)-2(5x-1)]/(5x-1)
=[(25x^2)/(5x-1)]-2
=25-2
=23
本回答被提问者和网友采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询