求解这道题目
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f(x,y)=(y-2)(sinx)ln(y+e^(x^2)) +x^2
f'散袭x(x,y)
=(y-2) [(sinx) ∂迹掘碧/∂xln(y+e^(x^2)) + ln(y+e^(x^2)).∂/姿举∂x (sinx) ] + 2x
=(y-2) [(sinx)[1/(y+e^(x^2))].∂/∂x(y+e^(x^2)) + ln(y+e^(x^2)).(cosx) ] + 2x
=(y-2) [(sinx)[1/(y+e^(x^2))].( 2x.e^(x^2)) + ln(y+e^(x^2)).(cosx) ] + 2x
f'x(1,2)
=0 + 2(1)
=2
f'散袭x(x,y)
=(y-2) [(sinx) ∂迹掘碧/∂xln(y+e^(x^2)) + ln(y+e^(x^2)).∂/姿举∂x (sinx) ] + 2x
=(y-2) [(sinx)[1/(y+e^(x^2))].∂/∂x(y+e^(x^2)) + ln(y+e^(x^2)).(cosx) ] + 2x
=(y-2) [(sinx)[1/(y+e^(x^2))].( 2x.e^(x^2)) + ln(y+e^(x^2)).(cosx) ] + 2x
f'x(1,2)
=0 + 2(1)
=2
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