八年级下分式数学题
展开全部
解：原式=[（x-y）/（x-y）^2 - y(x+y)/(x-y)(x-y) ] * xy/(y-1)
=[1/(x-y) - y/(x-y) ]*xy/(y-1)
=(1-y)/(x-y) * xy/(y-1)
=-(y-1)/(x-y) * xy/(y-1)
=-xy/(x-y)
=[1/(x-y) - y/(x-y) ]*xy/(y-1)
=(1-y)/(x-y) * xy/(y-1)
=-(y-1)/(x-y) * xy/(y-1)
=-xy/(x-y)
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
