已知电阻R1 R2 R3,电源电压为U,如何分别表示经过三个电阻的电流?
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根据你所画的电路图可知这是一个混联电路。
电阻R2与R3先并联,然后与R1串联。当电源电压为U时,通过R2的电流I2和通过R3的电流I3之和等于通过R1的电流I1,即
I2+I3=I1
电路的总电阻为:
R=R1+R2R3/(R2+R3)
总电流I=I1=U/R
=U/[R1+R2R3/(R2+R3)]
U2=U3=U-U1=U-I1R1
I2=U2/R2
=(U-U1)/R2
=(U-I1R1)/R2
={U-U/[R1+R2R3/(R2+R3)]×R1}/R2
I3=U3/R3
=(U-U1)/R3
=(U-I1R1)/R3
={U-U/[R1+R2R3/(R2+R3)]×R1}/R3。
电阻R2与R3先并联,然后与R1串联。当电源电压为U时,通过R2的电流I2和通过R3的电流I3之和等于通过R1的电流I1,即
I2+I3=I1
电路的总电阻为:
R=R1+R2R3/(R2+R3)
总电流I=I1=U/R
=U/[R1+R2R3/(R2+R3)]
U2=U3=U-U1=U-I1R1
I2=U2/R2
=(U-U1)/R2
=(U-I1R1)/R2
={U-U/[R1+R2R3/(R2+R3)]×R1}/R2
I3=U3/R3
=(U-U1)/R3
=(U-I1R1)/R3
={U-U/[R1+R2R3/(R2+R3)]×R1}/R3。
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