Question

已知函数f(x)=2x+3,g(2x-1)=f(x^2-1)求g(x+1)的解析式.

给出详细解答,谢谢.

Answer 1

g(2x-1)=f(x^2-1)=f{[1/2(2x-1+1)]^2-1},把2x-1替换成x+1，g(x+1)=f{[1/2(x+1+1)]^2-1}=f[1/4(x+2)^2-1]=2[1/4(x+2)^2-1]+3=1/2(x+2)^2+1

Answer 2

2×(t/2 +2)^0.5+1