Question

(x四次方-8x2y2+16y四次方）÷（2y+x）2÷（x-2y) 要 过程要详细

速度在线等

Answer 1

解：被除式是一个差的完全平方式
原式=（x²-4y²)²÷[(x+2y)²(x-2y)],被除式又是一个平方差式子
=[(x+2y)(x-2y)]²÷[(x+2y)²(x-2y)]
=(x+2y)²(x-2y)²÷[(x+2y)²(x-2y)]
=(x-2y)²÷(x-2y)
=x-2y

Answer 2

(x^4-8x2y2+16y^4）÷（2y+x）2÷（x-2y)
=(x^2-4y^2)^2÷（2y+x）2÷（x-2y)
=[(x-2y)(x+2y)]^2÷（2y+x）2÷（x-2y)
=(x-2y)^2(x+2y)^2÷（2y+x）2÷（x-2y)
=[(x-2y)^2(x+2y)^2÷（2y+x）2]÷（x-2y)
=[(x+2y)(x-2y)^2]/2÷（x-2y)
=[(x-2y)(x+2y)]/2
=(x^2-4y^2)/2
=1/2 x^2-2y^2