Question

如下:请各位高手帮忙解答一下,急!!!!!!!!!!!!我十分感谢,要写出过程

若(根号X-1)*(根号2-X)=(根号X-1*2-X)成立,试化简(X-4的绝对值+X的绝对值)

Answer 1

√(x - 1) * √(2 - x) = √[(x - 1) * (2 - x)].
故 x - 1 ≥ 0, 2 - x ≥ 0.
∴ 1 ≤ x ≤ 2.
∴ |x - 4| = 4 - x, |x| = x.
∴ |x - 4| + |x| = 4 - x + x = 4.