这微分怎么求:(x-y+1)dy/dx=1？
2个回答
展开全部
(x-y+1)dy/dx=1
dy/dx = 1/(x-y-1)
dx/dy= x-y -1
dx/dy -x = -y -1
The aux. equation
p-1=0
p= 1
let
xg= Ae^y
xp= By +C
xp' = B
xp'-xp=-y-1
B- (By +C) = -y-1
-By +(B-C) =-y-1
=>
-B=-1 and B-C=-1
B=1 and C=2
xp=y+2
通解
x=xg+xp=Ae^y +y+2
dy/dx = 1/(x-y-1)
dx/dy= x-y -1
dx/dy -x = -y -1
The aux. equation
p-1=0
p= 1
let
xg= Ae^y
xp= By +C
xp' = B
xp'-xp=-y-1
B- (By +C) = -y-1
-By +(B-C) =-y-1
=>
-B=-1 and B-C=-1
B=1 and C=2
xp=y+2
通解
x=xg+xp=Ae^y +y+2
来自：求助得到的回答
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
