Question

计算(根号3/2i-1/2)(-1/2+根号3/2i）

Answer 1

(根号3/2i-1/2)(-1/2+根号3/2i）=(√3/2i-1/2)²=（-√3i/2-1/2）²=（√3i+1）²/4
=（3i²+2√3i+1）/4=(-2+2√3i)/4=-1/2+√3i/2

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Answer 2

题目不是很明了.
若是:[√3/(2i)-1/2][-1/2+√3/(2i)]=[-1/2-(√3/2)i][-1/2-√3/(2i)]=-1/2+(√3/2)i
若是:[(√3/2)i-1/2][-1/2-(√3/2)i)]=[-1/2+(√3/2)i][-1/2-(√3/2)i]=1