Question

数学分式通分与约分

约分 (x²+xy)/(x+y)²
x²-y²/（x²-y²）
通分2xy/(x+y)²与x/x²-y²
x-y/2x+2y与xy/(x+y)²

Answer 1

约分
(x²+xy)/(x+y)²
=x(x+y)/(x+y)²
=x/(x+y）

x²-y²/（x²-y²）=1

通分
2xy/(x+y)²与x/x²-y²
2xy/(x+y)²=2xy(x-y)/[(x+y)²（x-y）]
x/(x²-y²)=x(x+y)/[(x+y)²(x-y)]

x-y/2x+2y与xy/(x+y)²
(x-y)/(2x+2y)=(x-y)(x+y)[2(x+y)²]=（x²-y²)/[2(x+y)²]
xy/(x+y)²=2xy/[2(x+y)²]

追问

x²-y²/（x-y）² 约分zm uzo !

追答

(x²-y²)/(x-y)²
=(x-y)(x+y)/(x-y)²
=(x+y)/(x-y)

Answer 2

你那个是2次方还是Z？

追问

2次方

追答

约分 x/x+y 第2个看不明白
通分 公因式为x/x+y 1/x+y