Question

在线等！急！！！！！初二二次根式算术题

化简1(.a-b)/(√a+√b)
2.(3+√3+√6)/(2+√2+√6)
3.(5+√6+√10+√15)/(√5+√2)

Answer 1

1(.a-b)/(√a+√b)
=(√a+√b)(√a-√b))/(√a+√b)
=√a-√b

2.(3+√3+√6)/(2+√2+√6)
=√3(√3+1+√2)/[√2(√2+1+√3)]
=√3/√2
=√3*√2/(√2*√2)
=√6/2

3.(5+√6+√10+√15)/(√5+√2)
=(5+√10+√6+√15)/(√5+√2)
=[√5(√5+√2)+√3(√2+√5)]/(√5+√2)
=[(√5+√3)(√2+√5)]/(√5+√2)
=√5+√3

Answer 2

1(.a-b)/(√a+√b)=(a-b)(√a-√b)/(√a+√b))(√a-√b)=(a-b)(√a-√b)/(a-b)=√a-√b
2.(3+√3+√6)/(2+√2+√6)=√3(√3+1+√2)/√2(√2+1+√3)=√3/√2=√6/2
3.(5+√6+√10+√15)/(√5+√2)=(5+√10+√6+√15)/(√5+√2)=[√5(√5+√2)+√3(√2+√5)]/(√5+√2)=(√5+√3)((√5+√2))/(√5+√2)=√5+√3

Answer 3

化简1(.a-b)/(√a+√b)
=【(√a)²-（√b）²】/(√a+√b）=(√a+√b）(√a-√b）/(√a+√b)=√a-√b
2.(3+√3+√6)/(2+√2+√6)
=√3(√3+1+√2)/√2(√2+1+√3)=√3/√2=√6/2
3.(5+√6+√10+√15)/(√5+√2)
=(√5+√2)(√5+√3)/(√5+√2)
=√5+√3

Answer 4

1(.a-b)/(√a+√b)
=（a-b）(√a-√b)/(√a+√b)(√a-√b)
=√a-√b
2.(3+√3+√6)/(2+√2+√6)
=6+3√2+3√6+2√3+√3.√2+√3.√6+2√6+√6.√2+√6√6
=12+6√2+6√6+6√3
3.(5+√6+√10+√15)/(√5+√2)
=【√5(√5+√2)+√3(√5+√2)】/(√5+√2)
=(√5+√2)(√5+√3）/(√5+√2)
=√5+√3