Question

初二下册数学题（分式化简）！！求救啊啊啊！！！老师们拜托啦！！化简过程也请帮我写出来吧~

……因为有一些东东打不出……用图片

Answer 1

解:原式=｛[(x+2)(x-2)/(x-2)²]｝-x/[x(x-2)]｝×[(x²-4)/x]
=｛[(x+2)/(x-2)]-1/(x-2)｝×[(x+2)(x-2)/x]
=｛[(x+2)-1]/(x-2)｝×[(x+2)(x-2)/x]
=[(x+1)/(x-2)]×[(x+2)(x-2)/x]
=(x+1)(x+2)/x

Answer 2

解：原式=[（x+2)(x-2)/(x-2)²-x/x(x-2)]*[(x²-4)/x]
=[(x+2)/ (x-2）-1/（x-2)] *[(x+2)(x-2)/x]
=(x+1)(x-2)*[(x+2)(x-2)/x]
=(x+1)(x+2)/x

Answer 3

叉烧包啊，看不到图

追问

怎么会！？