Question

一道数学计算题：分式的乘除~

（x的平方y的平方/x的平方-y的平方）的三次方 × （y的平方-x的平方/x的三次方y的平方）的平方 = ？

Answer 1

[x²y²/(x²-y²)]³×[(y²-x²)/x³y²]²
=x^6y^6/(x²-y²)³×(y²-x²)²/x^6y^4
=x^6y^6/(x²-y²)³×(x²-y²)²/x^6y^4
=y²/(x²-y²)

Answer 2

[ (x^2 y^2) / (x^2-y^2) ] ^3 × [ (y^2-x^2) / (x^3 y ^2) ] ^2
= (x^2 y^2)^3 / (x^2-y^2) ^3 × (y^2-x^2)^2 / (x^3 y ^2) ^2
= (x^6 y^6) / (x^2-y^2) ^3 × (x^2-y^2)^2 / (x^6 y^4)
= y^2 /(x^2-y^2)

Answer 3

[ x²y² / (x²-y²) ]³ × [（y²-x²) / x³y² ]²
=[ x²y² / (x²-y²) ] × [ x²y² / (x²-y²) ]² × [（y²-x²) / x³y² ]²
=[ x²y² / (x²-y²) ] ×[ x²y² / (x²-y²) × (y²-x²) / x³y² ]²
=[ x²y² / (x²-y²) ] × (1 / x²)
=y²/（x² - y²）

Answer 4

原式=[x²y²/(x²-y²)]²×[(y²-x²)/x³y²]²×x²y²/(x²-y²)
=[x²y²/(x²-y²)×(y²-x²)/x³y²]²×x²y²/(x²-y²)
=1/x²×x²y²/(x²-y²)
=y²/(x²-y²)

Answer 5

（x的平方-y的平方）分之 y的平方

追问

过程可以写一下吗