当x=2,y=2/5时,(x-y)(x-2y)-1/2(2x-3y)(x+2y)的值为( )
2011-03-03 · 知道合伙人教育行家
关注
展开全部
x=2,y=2/5
(x-y)(x-2y)-1/2(2x-3y)(x+2y)
=(x-y)(x-2y)-1/2(2x-2y-y)(x+2y)
=(x-y)(x-2y)-(x-y)(x+2y) +1/2 y(x+2y)
=(x-y)(x-2y-x-2y) +1/2 y(x+2y)
=-4y(x-y) +1/2 y(x+2y)
=-4xy + 4y^2 +1/2xy+y^2
=-7/2xy+5y^2
=-7/2*2*2/5 + 5*(2/5)^2
=-14/5+4/5
=-2
(x-y)(x-2y)-1/2(2x-3y)(x+2y)
=(x-y)(x-2y)-1/2(2x-2y-y)(x+2y)
=(x-y)(x-2y)-(x-y)(x+2y) +1/2 y(x+2y)
=(x-y)(x-2y-x-2y) +1/2 y(x+2y)
=-4y(x-y) +1/2 y(x+2y)
=-4xy + 4y^2 +1/2xy+y^2
=-7/2xy+5y^2
=-7/2*2*2/5 + 5*(2/5)^2
=-14/5+4/5
=-2
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询