计算：(a+1)(a²+1)(a的四次方+1)(a的八次方+1)=
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(a+1)(a^2+1)(a^4+1)(a^8+1)
=(a-1)(a+1)(a^2+1)(a^4+1)(a^8+1)/(a-1)
=(a^2-1)(a^2+1)(a^4+1)(a^8+1)/(a-1)
=(a^4-1)(a^4+1)(a^8+1)/(a-1)
=(a^8-1)(a^8+1)/(a-1)
=(a^16-1)/(a-1)
=(a-1)(a+1)(a^2+1)(a^4+1)(a^8+1)/(a-1)
=(a^2-1)(a^2+1)(a^4+1)(a^8+1)/(a-1)
=(a^4-1)(a^4+1)(a^8+1)/(a-1)
=(a^8-1)(a^8+1)/(a-1)
=(a^16-1)/(a-1)
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