Question

如图所示，∠AOB是平角，OC是射线，OD、OE分别是∠AOC、∠BOC的角平分线

若∠AOD=65°,请求出∠BOE、∠DOE的度数

Answer 1

因为∠AOD=65°，且OD为∠AOC角平分闷败线
所以∠AOC=130
所以∠BOC=180-130=50
OE为∠BOC角平蚂冲颤分线
所以∠BOE=∠COE=1/2∠BOC=25
∠DOE=∠判猜DOC+∠BOE=90

Answer 2

∵轮行 ∠AOD = 65
∴ ∠AOC = 2∠AOD = 2*65 = 130
∵ ∠AOB是平角
∴ ∠BOC = 180 - ∠AOC = 180-130 = 50
∴ ∠或桐岁BOE = 1/2 ∠BOC = 1/2 * 50 = 25
∠DOE = ∠COD+∠COE = 1/2*(∠AOC+∠BOC) = 1/2∠AOB = 1/衫睁2* 180 = 90

Answer 3

∠BOE=25°
∠DOE90°