Question

若a＜-b＜1,化简[（a+b)/（b+1）]的绝对值-（a+b）的绝对值/(b+1)÷(a+b)/(b+1)的值（求过程）

Answer 1

a<-b,a+b<0
-b<1,b+1>0
所以(a+b)/(b+1)<0
所以原式=[-(a+b)/(b+1)-(-a-b)]÷(a+b)/(b+1)
=-(a+b)/(b+1)÷(a+b)/(b+1)-(-a-b)÷(a+b)/(b+1)
=-1+(b+1)
=b

Answer 2

(x+y)(x-y)-(x+y)=0
(x+y)(x-y-1)=0

若x-y-1=0
y=x-1
则4x^2-x^2+2x-1+2x-x+1=0
3x^2-3x=0
3x(x-1)=0
x=0,x=1
y=x-1

若x+y=0
y=-x
则4x^2-x^2+2x+x=0
3x^2+3x=3x(x+1)=0
x=0,x=-1
y=-x

所以
x=0,y=-1
x=1,y=0
x=0,y=0
x=-1,y=1