Question

分别以XY为半径画同心圆(X>Y)，所得圆环的面积为14π，求式子[-6（x+y)²（x-y）³]²÷[3（x

求式子[-6（x+y)²（x-y)³]²÷[3（x ＋y）（x－y）²]²

Answer 1

πx²-πy²=14π
x²-y²=14
分子[-6（x+y)²（x-y)³]²=[-6（x²-y²)²(x-y)]²=[-1176（x-y)]²
分母[3（x ＋y）（x－y）²]²=[3（x²-y²）（x-y）]²=[42（x-y)]²
将（x-y）约掉，可得出答案为784

Answer 2

圆环面积=πx^2-πy^2=π(x+y)(x-y)=14π
所以(x+y)(x-y)=14
原式=[-6(x+y)^2*(x-y)^3]^2/[3(x+y)(x-y)^2]^2
=36(x+y)^4*(x-y)^6/[9(x+y)^2*(x-y)^4]
=4(x+y)^2*(x-y)^2
=4[(x+y)(x-y)]^2
=196*4
=784

Answer 3

πx²-πy²=14π
x²-y²=14
分子[-6（x+y)²（x-y)³]²=[-6（x²-y²)²(x-y)]²=[-1176（x-y)]²
分母[3（x ＋y）（x－y）²]²=[3（x²-y²）（x-y）]²=[42将（x-y）约掉，可得出答案为784

Answer 4

题目是这样吗？[-6（x+y)²（x-y）³]²÷3x

Answer 5

-6(xcvgr)