Question

log2为底x的对数＞log3为底2的对数怎么解呀？

Answer 1

log<2>x > log<3>2
lnx/ln2 > (ln2/ln3)
lnx > (ln2)^2/ln3
x > e^[(ln2)^2/ln3]

Answer 2

解：∵log2 x ＞log3 2
∴lgx／lg2＞log3 2，
lgx＞lg2×log3 2＝（lg2）^2/lg3
∴x＞10^[（lg2)^2/lg3]