Question

初一数学计算题

化简
6p^2qz^2 * (-p^3q^2) * 2/3pq * m^5
-6a^2b(x-y)^3 * 1/3ab^2(x-y)^2
-a(x^2-2x+1)
(a+b^2+c^3) * (-2a)
a^n * (a^n-a^2-2)
(a+b)(m+n)
(x+1)(x-2)
(3x-2y)(2x-3y)
(x+3)(x-1)-x(x-2)+1
(2y-6x+4)(-1/2x+1)

Answer 1

6p^2qz^2 * (-p^3q^2) * 2/3pq * m^5＝－4p^6q^4m^5z^2
-6a^2b(x-y)^3 * 1/3ab^2(x-y)^2＝－2a^3b^3（x-y）^5
-a(x^2-2x+1)＝－ax^2＋2ax－a
(a+b^2+c^3) * (-2a)＝－2a^2－2ab^2－2ac^3
a^n * (a^n-a^2-2)＝a^2n－a^(n＋2)－2a^n
(a+b)(m+n)＝am＋an＋bm＋bn
(x+1)(x-2)＝x^2－x－2
(3x-2y)(2x-3y)＝6x^2－13xy＋6y^2
(x+3)(x-1)-x(x-2)+1＝4x－2
(2y-6x+4)(-1/2x+1)＝－xy+3x^2-8x+2y+4