Question

计算下列方程组的解！！！各位···帮个忙？？？？

Answer 1

有②得xy=xy-5y+2x-10
2x-5y=10 ③
①×2-③得y=4/3
把y=4/3代入①得x=25/3
所以{x=4/3
y=25/3

Answer 2

x-5 = y+2......(1)
xy = (x-5)(y+2)......(2)
令x-5=y+2=t
则x=t+5，y=t-2，代入（2）
(t+5)(t-2)=t^2
t^2+3t-10=t^2
3t=10
t=10/3
x=t+5=10/3+5=25/3
y=t-2=10/3-2=4/3