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连OA、OD .则∠AOD=2∠ACD=30° 连OB,OC,OD.弧AB=弧BC=弧CD=>∠AOB=∠BOC=∠COD
∠AOB+∠BOC+∠COD+∠AOD=360° =>∠BOD=110° =>∠BAC=1/2∠BOD=55°
∠BPC=∠BAC-∠ACD=55°-15°=40°
∠AOB+∠BOC+∠COD+∠AOD=360° =>∠BOD=110° =>∠BAC=1/2∠BOD=55°
∠BPC=∠BAC-∠ACD=55°-15°=40°
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