(a+2/a²-2a+8/4-a²)÷a-2/a 急求
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原式=[(a+2)/a(a-2)-8/(a+2)(a-2)]×[a/(a-2)]
=×[a/(a-2)]
=[(a²+4a+4-8a)/a(a+2)(a-2)]×[a/(a-2)]
=[(a²-4a+4)/a(a+2)(a-2)]×[a/(a-2)]
=[(a-2)²/a(a+2)(a-2)]×[a/(a-2)]
=a(a-2)²/[a(a+2)(a-2)(a-2)]
=1/(a+2)
=×[a/(a-2)]
=[(a²+4a+4-8a)/a(a+2)(a-2)]×[a/(a-2)]
=[(a²-4a+4)/a(a+2)(a-2)]×[a/(a-2)]
=[(a-2)²/a(a+2)(a-2)]×[a/(a-2)]
=a(a-2)²/[a(a+2)(a-2)(a-2)]
=1/(a+2)
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