Question

要使关于X的方程5x-2m=3x-6m+1的解在-3与2之间,求适合m的整数值.

Answer 1

5x-2m=3x-6m+1
2x=-4m+1
x=-2m+1/2
-3<-2m+1/2<2
-7/4<-m<3/4
-3/4<m<7/4
m=0 m=1

追问

-1行吗

追答

不行
-1是小于-3/4

Answer 2

解:
2x = -4m + 1
x = -2m + 0.5
-3 < -2m + 0.5 < 2
-3/4 < m < 7/4
m = { 0 ,1}