解一道初一的分式方程（x+1)/(x+2)+(x+6)/(x+7)=(x+2)/(x+3)+(x+5)/(x+6)求x的
展开全部
（x+1)/(x+2)+(x+6)/(x+7)=(x+2)/(x+3)+(x+5)/(x+6)
(x+2-1)/(x+2)+(x+7-1)/(x+7)=(x+3-1)/(x+3)+(x+6-1)/(x+6)
1-1/(x+2)+1-1/(x+7)=1-1/(x+3)+1-1/(x+6)
1/(x+2)+1/(x+7)=1/(x+3)+1/(x+6)
(x+7+x+2)/(x+2)(x+7)=(x+6+x+3)/(x+3)(x+6)
(2x+9)/(x+2)(x+7)=(2x+9)/(x+3)(x+6)
所以2x+9=0
x=-4.5
经检验,x=-4.5是原方程得解
(x+2-1)/(x+2)+(x+7-1)/(x+7)=(x+3-1)/(x+3)+(x+6-1)/(x+6)
1-1/(x+2)+1-1/(x+7)=1-1/(x+3)+1-1/(x+6)
1/(x+2)+1/(x+7)=1/(x+3)+1/(x+6)
(x+7+x+2)/(x+2)(x+7)=(x+6+x+3)/(x+3)(x+6)
(2x+9)/(x+2)(x+7)=(2x+9)/(x+3)(x+6)
所以2x+9=0
x=-4.5
经检验,x=-4.5是原方程得解
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
