Question

为了改善办学条件，某中学计划购买部分A品牌电脑和B品牌课桌。

为了改善办学条件，某中学计划购买部分A品牌电脑和B品牌课桌。第一次，用9万元购买了A品牌电脑10台和B品牌课桌200张。第二次，用9万元购买了A品牌电脑12台和B品牌课桌120张。
（1）每台A品牌电脑与每张B品牌课桌的价格各是多少元？
（2）第三次购买时，销售商对一次购买量大的客户打折销售。规定：一次购买A品牌电脑35台以上（含35台），按九折销售。一次购买B品牌课桌600张以上（含600张）按八折销售。学校准备用27万元购买电脑和课桌，其中电脑不少于35台，课桌不少于600张，问有几种购买方案？请设计出来。
【注意：考点为《不等式组的应用》，要有详细的过程！】
很急的啊~~~~~~~~~

Answer 1

（1）解设电脑X元/台 课桌Y元/ 张 由题意得
10x+200y=90000 (1)
12x+120y=90000 (2)
整理得
x+20y=9000 (3)
x+10y=7500 (4)
(3)-（4) 得
10y=1500
y=150
把 y=150代入（4）得
x+10×150=7500
x=6000
∴x=6000
y=150
答：每台电脑售价6000元，桌子售价150元
第二题。。。。暂时想不起来怎么写了。。如果会写了的话明天给你答案

Answer 2

有两种方案 ： 列方程式 6000 X 0.9 x + 150 X 0.8 y =270000 其中 x>= 35 , y >=600 且x y都是整数
方案一： x= 35 , y= 675 即是买电脑35台 买课桌675 台
方案二：x= 36 , y = 630 即是买电脑36台 买课桌630台

Answer 3

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Wal-baby to a third set created of 3 break points 40-0, whilst Zhang Shuai struggling to save lots of the very first two, but still within the third opponent around the break. Thankfully, she rapidly finished the next game back broken, the Council points towards the 1-1. Paul made after both men came to the 3-3, Zhang Shuai break in the eighth inning to total victory ushered in his own serve game! She also did not encounter any danger ,6-3, the conclusion of the time-consuming 1 hour 55 minute fight. They serve the whole game in every aspects of the performance generally speaking, Zhang Shuai saved 14 break points in 10 of her next opponent will probably be No. 4 seed in the baby and also the Netherlands, the Czech girl who Safa Nuo between Krajicek .

Answer 4

【】可以招标，进行优选
【】可以网上比对，现在性价比高的