Question

化简求值 ﹙1/sin10°﹚-﹙√3/COS10°﹚

Answer 1

解：原式=1/sin10-√3/cos10
=(cos10-√3sin10)/sin10cos10
=2(1/2*cos10-√3/2*sin10)/sin10cos10
=2(sin30cos10-cos30sin10)/sin10cos10=4sin(30-10)/2sin10cos10
=4sin20/sin20=4

Answer 2

解：
原式=(1/sin10º)-(√3/cos10º)
=[cos10º-√3sin10º]/(sin10ºcos10º)
=4[(1/2)cos10º-(√3/2)sin10º]/(sin20º)
=4[sin(30º-10º)]/(sin20º)
=4