Question

急求VC6.0下用C语言编写的俄罗斯方块的源代码，急！！！

用C语言编写的能在VC下运行的俄罗斯方块源代码，在TC2.0下运行的请走开
邮箱：394283088＠qq.com发到这个邮箱就行，谢谢各位！

Answer 1

#include "stdio.h"穗槐
#include "string.h"
#include<stdlib.h>
#include <dos.h>
#include<conio.h>
#include <graphics.h> /*图形函数库*/
struct Food
{
int x;/*食物的横坐标*/
int y;/*食物的纵坐标*/
int yes;/*判断是否要出现食物的盯袜*/
}food;
struct Snake
{
int x[N];
int y[N];
int node;/猜则友*蛇的节数*/
int direction;/*蛇移动方向*/
int life;/* 蛇的生命,0活着,1死*/
}snake;
void Init(void)
{
int gd=DETECT,gm;
initgraph(&gd,&gm,"c:\\tc");
cleardevice();
}
void DrawK(void)
{
/*setbkcolor(LIGHTGREEN);*/
setcolor(11);
setlinestyle(SOLID_LINE,0,THICK_WIDTH);/*设置线型*/
for(i=50;i<=600;i+=10)/*画围墙*/
{
rectangle(i,40,i+10,49); /*上边*/
rectangle(i,451,i+10,460);/*下边*/
}
for(i=40;i<=450;i+=10)
{
rectangle(50,i,59,i+10); /*左边*/
rectangle(601,i,610,i+10);/*右边*/
}
}

void GamePlay(void)
{
randomize();/*随机数发生器*/

food.yes=1;/*1表示需要出现新食物,0表示已经存在食物*/
snake.life=0;/*活着*/
snake.direction=1;/*方向往右*/
snake.x[0]=100;snake.y[0]=100;/*蛇头*/
snake.x[1]=110;snake.y[1]=100;
snake.node=2;/*节数*/
PrScore();/*输出得分*/
while(1)/*可以重复玩游戏,压ESC键结束*/
{
while(!kbhit())/*在没有按键的情况下,蛇自己移动身体*/
{
if(food.yes==1)/*需要出现新食物*/
{
food.x=rand()%400+60;
food.y=rand()%350+60;
while(food.x%10!=0)/*食物随机出现后必须让食物能够在整格内,这样才可以让蛇吃到*/
food.x++;
while(food.y%10!=0)
food.y++;
food.yes=0;/*画面上有食物了*/
}
if(food.yes==0)/*画面上有食物了就要显示*/
{
setcolor(GREEN);
rectangle(food.x,food.y,food.x+10,food.y-10);
}
for(i=snake.node-1;i>0;i--)/*蛇的每个环节往前移动,也就是贪吃蛇的关键算法*/
{
snake.x[i]=snake.x[i-1];
snake.y[i]=snake.y[i-1];
}
/*1,2,3,4表示右,左,上,下四个方向,通过这个判断来移动蛇头*/
switch(snake.direction)
{
case 1:snake.x[0]+=10;break;
case 2: snake.x[0]-=10;break;
case 3: snake.y[0]-=10;break;
case 4: snake.y[0]+=10;break;
}
setcolor(4);/*画出蛇*/
for(i=0;i<snake.node;i++)
rectangle(snake.x[i],snake.y[i],snake.x[i]+10,
snake.y[i]-10);
delay(gamespeed);
setcolor(0);/*用黑色去除蛇的的最后一节*/
rectangle(snake.x[snake.node-1],snake.y[snake.node-1],
snake.x[snake.node-1]+10,snake.y[snake.node-1]-10);
} /*endwhile（！kbhit）*/
if(snake.life==1)/*如果蛇死就跳出循环*/
break;
for(i=3;i<snake.node;i++)/*从蛇的第四节开始判断是否撞到自己了，因为蛇头为两节，第三节不可能拐过来*/
{
if(snake.x[i]==snake.x[0]&&snake.y[i]==snake.y[0])
{
GameOver();/*显示失败*/
snake.life=1;
break;
}
}
if(snake.x[0]<55||snake.x[0]>595||snake.y[0]<55||
snake.y[0]>455)/*蛇是否撞到墙壁*/
{
GameOver();/*本次游戏结束*/
snake.life=1; /*蛇死*/
}
if(snake.life==1)/*以上两种判断以后,如果蛇死就跳出内循环，重新开始*/
break;
if(snake.x[0]==food.x&&snake.y[0]==food.y)/*吃到食物以后*/
{
setcolor(0);/*把画面上的食物东西去掉*/
rectangle(food.x,food.y,food.x+10,food.y-10);
snake.x[snake.node]=-20;snake.y[snake.node]=-20;
/*新的一节先放在看不见的位置,下次循环就取前一节的位置*/
snake.node++;/*蛇的身体长一节*/
food.yes=1;/*画面上需要出现新的食物*/
score+=10;
PrScore();/*输出新得分*/
}
key=bioskey(0);/*接收按键*/
if(key==ESC)/*按ESC键退出*/
break;
else
if(key==UP&&snake.direction!=4)
/*判断是否往相反的方向移动*/
snake.direction=3;
else
if(key==RIGHT&&snake.direction!=2)
snake.direction=1;
else
if(key==LEFT&&snake.direction!=1)
snake.direction=2;
else
if(key==DOWN&&snake.direction!=3)
snake.direction=4;
}/*endwhile(1)*/
}
void GameOver(void)
{
cleardevice();
PrScore();
setcolor(RED);
settextstyle(0,0,4);
outtextxy(200,200,"GAME OVER");
getch();
}
void PrScore(void)
{
char str[10];
setfillstyle(SOLID_FILL,YELLOW);
bar(50,15,220,35);
setcolor(6);
settextstyle(0,0,2);
sprintf(str,"score:%d",score);
outtextxy(55,20,str);
}
void Close(void)
{ getch();
closegraph();
}

void main(void)
{
Init();/*图形驱动*/
DrawK();/*开始画面*/
GamePlay();/*玩游戏具体过程*/
//Close();/*图形结束*/
GameOver();/*结束游戏*/
//PrScore();/*输出成绩*/

}

Answer 2

#include<stdio.h>
#include<stdlib.h>模迹
#include<windows.h>
#include<time.h>
#include<conio.h>

#define MOD 28
#define SIZE_N 19
#define SIZE_M 12

int cur_x,cur_y,score,mark,next,map[SIZE_N][SIZE_M],Gamespeed=300;
char key1,key;

int shape[28][6]={//这是个比较偷懒的老带方法，就是7种方块旦含并，加上旋转总共28种
{0,-1,0,-2,1,0}, {0,1,1,0,2,0}, {-1,0,0,1,0,2}, {0,-1,-1,0,-2,0},
{0,-1,0,1,-1,0}, {0,1,1,0,-1,0}, {1,0,0,-1,0,1}, {1,0,-1,0,0,-1},
{-1,1,0,1,1,0}, {0,-1,1,0,1,1}, {-1,0,0,-1,1,-1}, {-1,-1,-1,0,0,1},
{-1,0,0,1,1,1}, {0,1,1,-1,1,0}, {-1,0,0,1,1,1}, {0,1,1,-1,1,0},
{-1,0,0,-1,0,-2}, {-1,0,-2,0,0,1}, {0,1,0,2,1,0}, {0,-1,1,0,2,0},
{0,1,1,0,1,1}, {0,-1,1,0,1,-1}, {-1,0,0,-1,-1,-1}, {-1,0,-1,1,0,1},
{0,1,0,2,0,3}, {1,0,2,0,3,0}, {0,-1,0,-2,0,-3}, {-1,0,-2,0,-3,0}
};

void gotoxy(int x,int y){//gotoxy在TC中是在system.h库文件里的一个函
COORD c;
c.X=x-1; c.Y=y-1;
SetConsoleCursorPosition (GetStdHandle(STD_OUTPUT_HANDLE), c);
}
void Gameover(){//游戏结束的判断
int i,j,flag=0;
for(j=1;j<SIZE_M-1;j++){
if(map[1][j]!=0){
flag=1;break;
}
}
if(flag==1){
for(i=1;i<SIZE_N-1;i++){
gotoxy(2,i+1);
for(j=1;j<SIZE_M-1;j++){
printf("□");
}puts("");
}
gotoxy(7,9);
printf("GAME OVER!");
gotoxy(1,SIZE_N+1);
exit(0);
}
}
void ShowMap(int id){
int i,j;
gotoxy(1,1);
if(id!=-1){
for(i=0;i<SIZE_N;i++){
for(j=0;j<SIZE_M;j++){
if(i==0&&j==0 || i==0&&j==SIZE_M-1 || j==0&&i==SIZE_N-1 || j==SIZE_M-1&&i==SIZE_N-1)printf(" ");
else if(i==0 || i==SIZE_N-1)printf("--");
else if(j==0 || j==SIZE_M-1)printf("|");
else if(map[i][j]==2) printf("■");
else if(i==cur_x+shape[id][0] && j==cur_y+shape[id][1] ||
i==cur_x+shape[id][2] && j==cur_y+shape[id][3] ||
i==cur_x+shape[id][4] && j==cur_y+shape[id][5] ||
i==cur_x && j==cur_y)
printf("■");
else if(map[i][j]==0) printf(" ");
}
if(i==1)printf(" next:");
if(i==11)printf(" score : %d",score);
if(i==14)printf(" speed : %d",score/100+1);
puts("");
}
}
else {
mark=1;
for(i=0;i<SIZE_N;i++){
for(j=0;j<SIZE_M;j++){
if(i==0&&j==0 || i==0&&j==SIZE_M-1 || j==0&&i==SIZE_N-1 || j==SIZE_M-1&&i==SIZE_N-1)printf(" ");
else if(i==0 || i==SIZE_N-1)printf("--");
else if(j==0 || j==SIZE_M-1)printf("|");
else if(map[i][j]==2) printf("■");
else if(map[i][j]==0) printf(" ");
}
if(i==1)printf(" next:");
if(i==11)printf(" score : %d",score);
if(i==14)printf(" speed : %d",score/100+1);
puts("");
}
}
/*对于next 方块的处理，先擦除再画图*/
for(i=2;i<=10;i++){
for(j=23;j<=34;j++){
gotoxy(j+1,i+1);printf(" ");
}
}
gotoxy(29,6); printf("■");
for(i=0;i<6;i=i+2){
gotoxy(29+2*shape[next][i+1],6+shape[next][i]); printf("■");
}
Sleep(Gamespeed);
}

void init(int id){//初始化函数，cur_x，cur_y是全局变量，标记了移动方块的位置
memset(map,0,sizeof(map));
for(int i=0;i<SIZE_N;i++){
for(int j=0;j<SIZE_M;j++)
if(i==SIZE_N-1 || j==0 || j==SIZE_M-1)
map[i][j]=-1;
}
cur_x=0; cur_y=6;
ShowMap(id);
}

int judge_in(int x,int y,int id){//判断是否出界，或者说是否合法
if(map[x][y]!=0)return 0;
for(int i=0;i<6;i=i+2){
if(map[ x+shape[id][i] ][ y+shape[id][i+1] ]!=0)return 0;
}return 1;
}

void fun_score(){//得分，擦除行的闪烁，还有图形的向下平移
for(int i=1;i<SIZE_N-1;i++){
int flag=0;
for(int j=1;j<SIZE_M-1;j++){
if(map[i][j]!=2){ flag=1;break; }
}
if(flag==0){
int k=3;
while(k--){
gotoxy(2,i+1);
for(int ii=1;ii<SIZE_M-1;ii++){
if(map[i][ii]==2){
if(k%2==1)printf(" ");
else printf("■");
}
}Sleep(100);
}
for(int ii=i;ii>1;ii--){
for(int jj=1;jj<SIZE_M-1;jj++)map[ii][jj]=map[ii-1][jj];
}
ShowMap(-1);
score+=10;
if(score%100==0 && score!=0)Gamespeed-=50;
}
}
}

int main(){
int i,id,set=1;

srand(time(NULL));
id=rand()%MOD; id=(id+MOD)%MOD;
next=rand()%MOD; next=(next+MOD)%MOD;

init(id);

while(1){
Here: mark=0;
if(set==0){
id=next;
next=rand()%MOD; next=(next+MOD)%MOD;
cur_x=0;cur_y=6;
set=1;
}

while(!kbhit()){
Gameover();
if(judge_in(cur_x+1,cur_y,id)==1) cur_x++;
else {
map[cur_x][cur_y]=2;
for(i=0;i<6;i=i+2)
map[ cur_x+shape[id][i] ][ cur_y+shape[id][i+1] ]=2;
set=0;
}
fun_score();
if(mark!=1)ShowMap(id);
goto Here;
}//end of while(!kbhit())

key=getch();
if(key1==-32 && key==72){
int tmp=id;
id++;
if( id%4==0 && id!=0 )id=id-4;
if(judge_in(cur_x,cur_y,id)!=1)id=tmp;
}
else if(key1==-32 && key==80 && judge_in(cur_x+1,cur_y,id)==1)cur_x++;
else if(key1==-32 && key==75 && judge_in(cur_x,cur_y-1,id)==1)cur_y--;
else if(key1==-32 && key==77 && judge_in(cur_x,cur_y+1,id)==1)cur_y++;
else if(key==27)return 0;
key1=key;
}return 0;
}

Answer 3

用VC 的SDK写的(没有用到MFC), 要么隐源?

留下邮箱桥衡, 我发给你.

发给你了... 用这个9392525**@qq.com 邮箱发灶消态给你的.... 记得给分...

追问

你给的是c++的，我要的是c语言的

追答

我不想解释了.....

Answer 4

俄罗斯方块

Answer 5

c#的要不？我发你了