几道因式分解 跪求高手帮忙了 小弟很急 在线等!!!!!!!!!!!!!
1a^2-2a(b+c)+(b+c)^22(x^2-5)^2+8(x^2-5)+163(3x+2y)^2-(2x+3y)^24x^6-10x^3+255(x-2y)^2-...
1 a^2-2a(b+c)+(b+c)^2
2 (x^2-5)^2+8(x^2-5)+16
3 (3x+2y)^2-(2x+3y)^2
4 x^6-10x^3+25
5 (x-2y)^2-8(x-2y)+16
6 2x^3y^3+4x^2y^2+2xy
求高手帮忙了啊 麻烦写下计算过程 不要一次写答案 跪求高手帮忙 在线等!!! 展开
2 (x^2-5)^2+8(x^2-5)+16
3 (3x+2y)^2-(2x+3y)^2
4 x^6-10x^3+25
5 (x-2y)^2-8(x-2y)+16
6 2x^3y^3+4x^2y^2+2xy
求高手帮忙了啊 麻烦写下计算过程 不要一次写答案 跪求高手帮忙 在线等!!! 展开
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1 a^2-2a(b+c)+(b+c)^2
=(a-b-c)^2
2 (x^2-5)^2+8(x^2-5)+16
=(x^2-5+4)^2
=(x^2-1)^2
=[(x+1)(x-1)]^2
=(x+1)^2(x-1)^2
3 (3x+2y)^2-(2x+3y)^2
=(3x+2y-2x-3y)(3x+2y+2x+3y)
=(x-y)(5x+5y)
=5(x-y)(x+y)
4 x^6-10x^3+25
=(x^3-5)^2
5 (x-2y)^2-8(x-2y)+16
=(x-2y-4)^2
6 2x^3y^3+4x^2y^2+2xy
=2xy(x^2y^2+2xy+1)
=2xy(xy+1)^2
=(a-b-c)^2
2 (x^2-5)^2+8(x^2-5)+16
=(x^2-5+4)^2
=(x^2-1)^2
=[(x+1)(x-1)]^2
=(x+1)^2(x-1)^2
3 (3x+2y)^2-(2x+3y)^2
=(3x+2y-2x-3y)(3x+2y+2x+3y)
=(x-y)(5x+5y)
=5(x-y)(x+y)
4 x^6-10x^3+25
=(x^3-5)^2
5 (x-2y)^2-8(x-2y)+16
=(x-2y-4)^2
6 2x^3y^3+4x^2y^2+2xy
=2xy(x^2y^2+2xy+1)
=2xy(xy+1)^2
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1. (a-b-c)^2
2 (x^2-5)^2+8(x^2-5)+16=(x^2-5+4)^2=(x-1)^2*(x+1)^2
3 (3x+2y)^2-(2x+3y)^2=(5x+5y)(x-y)=5(x+y)(x-y)
4 x^6-10x^3+25=(x^3-5)^2
5 (x-2y)^2-8(x-2y)+16=(x-2y-4)^2
6 2x^3y^3+4x^2y^2+2xy=2xy(xy+1)^2
2 (x^2-5)^2+8(x^2-5)+16=(x^2-5+4)^2=(x-1)^2*(x+1)^2
3 (3x+2y)^2-(2x+3y)^2=(5x+5y)(x-y)=5(x+y)(x-y)
4 x^6-10x^3+25=(x^3-5)^2
5 (x-2y)^2-8(x-2y)+16=(x-2y-4)^2
6 2x^3y^3+4x^2y^2+2xy=2xy(xy+1)^2
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=[a-(b+c)]^2
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1 a^2-2a(b+c)+(b+c)^2
=(a-b-c)²
2 (x^2-5)^2+8(x^2-5)+16
=(x²-5+4)²
=(x²-1)²
=(x+1)²(x-1)²
3 (3x+2y)^2-(2x+3y)^2
=(3x+2y+2x+3y)(3x+2y-2x-3y)
=5(x+y)(x-y)
4 x^6-10x^3+25
=(x³-5)²
5 (x-2y)^2-8(x-2y)+16
=(x-2y-4)²
6 2x^3y^3+4x^2y^2+2xy
=2xy(x²y²+2xy+1)
=2xy(xy+1)²
=(a-b-c)²
2 (x^2-5)^2+8(x^2-5)+16
=(x²-5+4)²
=(x²-1)²
=(x+1)²(x-1)²
3 (3x+2y)^2-(2x+3y)^2
=(3x+2y+2x+3y)(3x+2y-2x-3y)
=5(x+y)(x-y)
4 x^6-10x^3+25
=(x³-5)²
5 (x-2y)^2-8(x-2y)+16
=(x-2y-4)²
6 2x^3y^3+4x^2y^2+2xy
=2xy(x²y²+2xy+1)
=2xy(xy+1)²
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=(a-b-c)^2
=(x^2-1)^2=(x-1)^2*(x+1)^2
=(3x+2y-2x-3y)(3x+2y+2x+3y)=5(x-y)(x+y)
=(x^3-5)^2
=(x-2y-4)^2
=2xy(x^2y^2+2xy+1)=2xy(xy+1)^2
=(x^2-1)^2=(x-1)^2*(x+1)^2
=(3x+2y-2x-3y)(3x+2y+2x+3y)=5(x-y)(x+y)
=(x^3-5)^2
=(x-2y-4)^2
=2xy(x^2y^2+2xy+1)=2xy(xy+1)^2
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1=a[a-(b+c)]+(b+c)[b+c-a]=(b+c-a)^2
2=(x^2-5-4)^2=(x^2-1)^2
3=(3x+2y+2x+3y)(3x+2y-2x-3y)=5(x+y)(x-y)=5x^2-5y^2
4=(x^3-5)^2
5=(x-2y-4)^2
6=2xy[(xy)^2+2xy+1]=2xy(xy+1)^2
2=(x^2-5-4)^2=(x^2-1)^2
3=(3x+2y+2x+3y)(3x+2y-2x-3y)=5(x+y)(x-y)=5x^2-5y^2
4=(x^3-5)^2
5=(x-2y-4)^2
6=2xy[(xy)^2+2xy+1]=2xy(xy+1)^2
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