Question

xcos5xdx求不定积分

请高手帮忙，请详细到答案，谢谢

Answer 1

朋友，详细过程如图rt，希望能帮到你解决问题

Answer 2

本题不定积分计算过程如下：
∫xcos5xdx
=(1/5)∫xcos5xd5x
=(1/5)∫xdsin5x
=(1/5)xsin5x-(1/5)∫sin5xdx
=(1/5)xsin5x-(1/25)∫sin5xd5x
=(1/5)xsin5x+(1/25)cos5x+c.

Answer 3

分部积分求xcos5xdx的不定积分

Answer 4

∫xcos(5x) dx
=(1/5)∫x dsin(5x)
=(1/5)x.sin(5x) -(1/5)∫sin(5x) dx
=(1/5)x.sin(5x) +(1/25)cos(5x) +C

Answer 5

xcos5xdx
=(1/5)xd(sin5x)
=(1/5)(xsin5x-sin5xdx)
=（1/5）(xsin5x+1/5cos5x)+C
=（1/5）xsin5x+(1/25)cos5x+C