Question

1 4(x-3)²-25(x-2)²=0 2 （2x+1)+4(2X+1)+4=0 3 (x+1)(x+3)=6x+2 4 (x-2)(x-3)=6 用因式分解法

Answer 1

1 4(x-3)²-25(x-2)²=0
[2(x-3)-5(x-2)][2(x-3)+5(x-2)]=0
(2x-6-5x+10)(2x-6+5x-10)=0
(-3x+4)(7x-16)=0
-3x+4=0 7x-16=0
x=4/3或x=16/7

2 （2x+1)²+4(2X+1)+4=0 你这题是不是少了一个“平方号”
(2x+1+2)²=0
（2x+3)²=0
x=-3/2

3 (x+1)(x+3)=6x+2
x²+4x+3-6x-2=0
x²-2x+1=0
(x-1)²=0
x=1
4 (x-2)(x-3)=6
x²-5x+6-6=0
x²-5x=0
x(x-5)=0
x=0 或x=5

Answer 2

1 4(x-3)²-25(x-2)²=0
(2x-6+5x-10)(2x-6-5x+10)=0
(7x-16)(-3x+4)=0
x=16/7,x=4/3

2 （2x+1)²+4(2X+1)+4=0
(2x+1+2)²=0
(2x+3)²=0
x=-3/2

3 (x+1)(x+3)=6x+2
x²+4x+3-6x-2=0
x²-2x+1=0
(x-1)²=0
x=1

4 (x-2)(x-3)=6
x²-5x+6=6
x²-5x=0
x(x-5)=0
x=0,x=5