Question

数学题，坐等！！！！！

需要具体步骤，不要发公式，也不要发“不会”之类的，给我具体的步骤，不要让我自己去带入公式，要不然没分！！！！
分解因式

Answer 1

x^3+x^2+x-y^3-y^2-y=(x^3-y^3)+(x^2-y^2)+(x-y)=(x-y)(x^2+xy+y^2)+(x+y)(x-y)+(x-y)=(x-y)[x^2+xy+y^2+x+y+1].

a^6-3a^4b+3a^2b^2-b^3=(a^6-a^4b)-(2a^4b-2a^2b^2)+(a^2b^2-b^3)=a^4(a^2-b)-2a^2b(a^2-b)+b2(a^2-b)=(a^2-b)(a^4-2a^2b+b2)=(a^2-b)^3.

a^3+6a^2b+12ab^2+8b^3=(a^3+8b^3)+(6a^2b+12ab^2)=(a+2b)(a^2-2ab+4b^2)+6ab(a+2b)=(a+2b)(a^2-2ab+4b^2+6ab)=(a+2b)(a^2+4ab+4b^2)=(a+2b)^3.

将上式中的a用-b代替，b用a代替，记得此式8a^3-12a^2b+6ab^2-b^3=(2a-b)^3.

27x^3-108x^2y+144xy^2-64y^3=(27x^3-64y^3)-(108x^2y-144xy^2)=[(3x)^3-(4y)^3]-36xy(3x-4y)=(3x-4y)[9x^2+12xy+16y^2-36xy]=(3x-4y)[9x^2-24xy+16y^2]=(3x-4y)^3.

1+12x^2y^2+48x^4y^4+64x^6y^6=(1+64x^6y^6)+(12x^2y^2+48x^4y^4)=[1^3+(4x^2y^2)^3]+12x^2y^2(1+4x^2y^2)=(1+4x^2y^2)[1+4x^2y^2+16x^4y^4+12x^2y^2]=(1+4x^2y^2)[1+16x^2y^2+16x^4y^4]=(1+4x^2y^2)^3.

27x^3-9x^2y+xy^2-y^3/27=(27x^3-y^3/27)+(-9x^2y+xy^2)=[(3x)^3-(y/3)^3]-3xy(3x-y/3)=(3x-y/3)[9x^2+xy+y^2/9-3xy]=(3x-y/3)^3.

1-3(x-y)+3(x-y)^2-(x-y)^3=1-(x-y)-2(x-y)+2(x-y)^2+(x-y)^2-(x-y)^3=[1-(x-y)]-2(x-y)[1-(x-y)]+(x-y)^2[1-(x-y)]=[1-(x-y)][1-2(x-y)+(x-y)^2]=[1-(x-y)]^3.

x^6-3x^4y^2+3x^2y^4-y^6=(x^6-y^6)-(3x^4y^2-3x^2y^4)=(x^2-y^2)[x^4+x^2y^2+y^4]-3x^2y^2(x^2-y^2)=(x^2-y^2)[x^4-2x^2y^2+y^4]=(x^2-y^2)^3.

1-12a^2b^2+48a^4b^4-64a^6b^6=(1-64a^6b^6)-(12a^2b^2-48a^4b^4)=(1-4a^2b^2)[1+4a^2b^2+16a^4b^4]-12a^2b^2(1-4a^2b^2)=(1-4a^2b^2)[1+4a^2b^2+4a^4b^4]=(1-4a^2b^2)^3.

Answer 2

这些很简单啊 你上初二上的最后一章好好看一遍就全会啦

Answer 3

第1题